Răspuns :
200g xg yg
Zn + 2HCl =ZnCl2 + H2
65g 136g 2g
MZnCl2=65+2.35,5=136------>1mol=136g
se afla x din ec.
x=200.136 :65=418,36 g ZnCl2
se afla y
y=200.2 :65=6,15 g hidrogen
se afla nr. moli de H
n=m: M
n=6,15g : 2g/moli=3,075 moli hidrogen
200g xg yg
Zn + 2HCl =ZnCl2 + H2
65g 136g 2g
MZnCl2=65+2.35,5=136------>1mol=136g
se afla x din ec.
x=200.136 :65=418,36 g ZnCl2
se afla y
y=200.2 :65=6,15 g hidrogen
se afla nr. moli de H
n=m: M
n=6,15g : 2g/moli=3,075 moli hidrogen