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Log3 x = 1 + logx 9 urgent va rog

Răspuns :

Semaka2

x>0 x=/=1

log₃x=1+log(x)3²

log₃x=1+2log(x)3

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log(a)b=1/log(b)a

Ecuatia   devine

log₃x=1+2/log₃x

log₃x=y

y=1+2/y

y²=y+2

y₂-y-2=0

y1= -1   y2=2

log₃x=-1=>x=3^(-1)=1/3

log₃x=2=> x=3²=9

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