1 mol glucoza contine 6x6,022x10la23 atomi C si 12x6,022x10la23 atomi H
=> daca la 6x6,022x10la23 at C................... 1 mol glucoza
la 6x2x10la22 at. C ........................ n moli
=> n = 2×10la22/6,022×10la23 = 0,0332 moli glucoza
=> la 0,0332 moli glucoza vom avea ............ a at H
daca la 1 mol glucoza am............................. 12x6,022x10la23 at H
=> a = 2,4×10la23 at H
b) niu = N / N.a => N = niuxN.a = 0.03326,022×10la23 =2×10la22