a) 2Na+Cl2=2NaCl
m Na=69kg
A( masa atomică) Na = 23 Kg/kmol
N kmoli = A/m
N kmoli =69/23=3 kmoli
A Cl =35,5
1 kmol Cl2 =2 * 35,5 = 71 Kg
2 kmol Na......1 kmol Cl2
3 kmoli Na......x kmoli Cl2
X=1,5 kmoli Cl2 (1kmol=1000moli)
1,5 kmoli =1500moli Cl2
b) M NaCl = 23+35,5=58,5
2moli NaCl=2 * 58,5 = 117 kg
23 Kg Na.........117 Kg NaCl
69.....................y
y = 351 kg
351×80/100= 280.8
c) 117 Kg NaCl .....71Kg Cl
100Kg NaCl........z
z = 60,68 % Cl
