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Sa se calculeze:
a).(m-1)(m la a 2+m+1)
b).(2a+3b)(4a la a 2-6ab+9b la a 2)
c).(a-1)(a+1)(a la 2+a+1)(a la a 2-a+1)
d).(x-1)(x+1)(x la a 4+x la a 2+1)(x la a 12+x la 6+1)
Va roog,macar primele 2

Răspuns :

Lucasela

a).(m-1)(m²+m+1)=m³-1


b).(2a+3b)(4a²-6ab+9b²)=8a³+27b³


c).(a-1)(a+1)(a²+a+1)(a²-a+1)=(a³-1)(a³+1)=a^6  -1


d).(x-1)(x+1)(x^4+x²+1)(x^12+x^6+1)=

=(x²-1)(x^4+x²+1)(x^12+x^6+1)

=(x^6 -1)(x^12+x^6+1)

=x^18  -1

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