z⁴=(-1-i√3)/2=-1/2-i√3/2
lz⁴l=√[(-1/2)²+(-√3/2)²]=√(1/4+3/4)=1
Pui numarul sub forma trigonometrica
cosx= -1/2
sinx=-√3/2
Sinusul si cosinusul negative=> x ∈ cadran 3
x=π+π/3=4π/3
z⁴=cos4π/3+isin 4π/3
Aplici formula
z=cos(x+2kπ)/4+isin(x+2kπ) k={0,1,2,3,}
zo=cosx/4+isinx/4
z1=cos(x+2π)/4+isin(x+2π)/4
z2=c0s(x+4π)/4+isin(x+4π)/4
z3=cos(x+6π)/4+isin(x+6π)/4
