Răspuns :
x² + x - 12 = 0
Δ = b² - 4ac = 1 - 4 ×(-12) = 49
x1 = (-b +√Δ) / 2a = (-1 + 7)/2 = 6/2 = 3
x2 = (-b - √Δ) / 2a = (-1 - 7) /2 = - 8/2 = -4
S = {-4 ; 3}
x² + x - 12 = 0
Δ = b² - 4ac = 1 - 4 ×(-12) = 49
x1 = (-b +√Δ) / 2a = (-1 + 7)/2 = 6/2 = 3
x2 = (-b - √Δ) / 2a = (-1 - 7) /2 = - 8/2 = -4
S = {-4 ; 3}