M,KCl03= 122,5g/mol
-calculez masa de clorat pur
p=m,px100/m,i---> m,p= 500x98/100g= 490g ..........este masa practica
calculez masa teoretica de clorat din care rezulta 4,5mol O2
1mol...................................1,5mol
KClO3--------> KCl + 3/2O2
122,5g............................1,5mol
x........................................4,5mol
x= m,teor= 367,7g clorat
randamentul=367,7x100/490=......................calculeaza
