Răspuns :
[tex]\left\{\begin{matrix}
8b + 4f = 100 \: \ | \times ( - 11)& \\
18b + 11f = 235 \: | \times 4 &
\end{matrix}\right.[/tex]
[tex]\left\{\begin{matrix}
- 88b - 44f = - 1100 & \\
72b + 44f = 940&
\end{matrix}\right.[/tex]
[tex] - 88b + 72b - 44f + 44f = - 1100 + 940[/tex]
[tex] - 16b = - 160 \: | \div ( - 16)[/tex]
[tex]b = 10[/tex]
[tex]8b + 4f = 100[/tex]
[tex]8 \times 10 + 4f = 100[/tex]
[tex]80 + 4f = 100[/tex]
[tex]4f = 100 - 80[/tex]
[tex]4f = 20 \: | \div 4[/tex]
[tex]f = 5[/tex]
8b + 4f = 100 \: \ | \times ( - 11)& \\
18b + 11f = 235 \: | \times 4 &
\end{matrix}\right.[/tex]
[tex]\left\{\begin{matrix}
- 88b - 44f = - 1100 & \\
72b + 44f = 940&
\end{matrix}\right.[/tex]
[tex] - 88b + 72b - 44f + 44f = - 1100 + 940[/tex]
[tex] - 16b = - 160 \: | \div ( - 16)[/tex]
[tex]b = 10[/tex]
[tex]8b + 4f = 100[/tex]
[tex]8 \times 10 + 4f = 100[/tex]
[tex]80 + 4f = 100[/tex]
[tex]4f = 100 - 80[/tex]
[tex]4f = 20 \: | \div 4[/tex]
[tex]f = 5[/tex]
Metoda comparatiei
8 baieti ......... 4 fete ....... 100 kg l : 4
2 baieti .......... 1 fata ........ 25 kg l x 11
18 baieti ........ 11 fete ...... 235 kg
___________________________ egalizez nr. fete
22 baieti ........11 fete ........ 275 kg
18 baieti ......... 11 fete ........ 235 kg
_________________________ scad relatiile
4 baieti ............./.............. 40 kg
40 kg : 4 = 10 kg → culege un baiat
Din relatia: 2 baieti .......... 1 fata ........ 25 kg, aflam ce cantitate culege o fata
25 kg - 2 x 10 kg = 5 kg culege o fata