Răspuns :
[tex] \frac{x}{y} = \frac{3}{8} = > x = 3 \: \: \: y = 8 \\ \\ a) \frac{x + y}{y} = \frac{3 + 8}{8} = \frac{11}{8} \\ \\ \\ b) \frac{x}{y - x} = \frac{3}{8 - 3} = \frac{3}{5} \\ \\ \\ c) \frac{x}{3 \times y} = \frac{3}{3 \times 8} = \frac{3}{24} = \frac{1}{8} \\ \\ \\ \\d) \frac{8 \times x + 3 \times y}{9 \times y} = \frac{8 \times 3 + 3 \times 8}{9 \times 8} = \frac{24 + 24}{72} = \frac{48}{72} = \frac{2}{3} [/tex]
\frac{x}{y} = \frac{3}{8} = > x = 3 \: \: \: y = 8 \\ \\ a) \frac{x + y}{y} = \frac{3 + 8}{8} = \frac{11}{8} \\ \\ \\ b) \frac{x}{y - x} = \frac{3}{8 - 3} = \frac{3}{5} \\ \\ \\ c) \frac{x}{3 \times y} = \frac{3}{3 \times 8} = \frac{3}{24} = \frac{1}{8} \\ \\ \\ \\d) \frac{8 \times x + 3 \times y}{9 \times y} = \frac{8 \times 3 + 3 \times 8}{9 \times 8} = \frac{24 + 24}{72} = \frac{48}{72} = \frac{2}{3}