Din teorie stim ca:
md = masa dizolvatului
ms = masa solutiei = md + m.apa
c% conc. solutie = mdx100/ms
a)
md = 40 g , m.apa = 260 g
=> ms = 40 + 260 = 300 g solutie
=> c% = 40x100/300 = 13,33%
b)
md = 40 g , m.alcool = 360 g
=> ms = 40 + 360 = 400 g solutie
=> c% = 40x100/400 = 10%
c)
ms = 250 g
c% = 35%
=> md = msxc%/100 = 250x35/100
=> md= 87,5 g
d)
- 20% = 20 g iod dizolvat in 100 g solutie
=> md = 20 g , m.solvent = ms - md = 100 - 20 = 80 g alcool
- 25% = 25 g zahar dizolvat in 100 g solutie
=> md = 25 g , m.apa = ms - md = 100 - 25 = 75 g apa
- 40% = 40 g piatra vanata dizolvata in 100 g solutie
=> md = 40 g , m.apa = ms - md = 100 - 40 = 60 g apa
