Răspuns :
dupa parerea mea, problema este incompleta
-calculez moli Al
niu=N/N,A=6,023X10²⁴at/6,023X10²³at/mol= 10mol
din ecuatia chimica ,deduc moli de acid si de H2
2mol.........3mol.....................................3mol
2Al + 3H2SO4--------> Al2(SO4)3 + 3H2
10mol.........x= 15mol..................................y=15molH2
-Calculez md si ms din relatia c= mdx100/ms
md= niuxM,H2SO4= 15x98gH2SO4=1470g
ms= mdx100/c= 1470x100/98 g=........................calculeaza !!!
reactiile care mai au loc
Al2(SO4)3 + 3BaCl2----> 3BaSO4 + 2AlCl3
H2 + Cl2---> 2HCl