[tex]4 \sqrt{18} - 2 \sqrt{8} - \sqrt{3}(3 \sqrt{12} - 1) = \\ \\ 4 \times 3 \sqrt{2} - 2 \times 2 \sqrt{2} - \sqrt{3}(3 \times 2 \sqrt{3} - 1) = \\ \\ 12 \sqrt{2} - 4 \sqrt{2} - \sqrt{3}(6 \sqrt{3} - 1) = \\ \\ (12 \sqrt{2} - 4 \sqrt{2}) - \sqrt{3}(6 \sqrt{3} - 1) = \\ \\ 8 \sqrt{2} - 18 + \sqrt{3} [/tex]
