👤
a fost răspuns

d) (2x-3)(3x-2)+(1-3x)(2x -1)+(x-2)(2x^2-3x+3)

Răspuns :

Trombolistul

(2x-3)(3x-2)+(1-3x)(2x-1)+(x-2)(2x²-3x+3)=


6x²-4x-9x+6+2x-1-6x²+3x+2x³-3x²+3x-4x²+6x-6=


(6x²-6x²-3x²-4x²)+(-4x-9x+2x+3x+3x+6x)+(6-1-6)+2x³=


-3x²-4x²+x-1+2x³=


(-3x²-4x²)+x-1+2x³=


-7x²+x-1+2x³

Alte intrebari