Răspuns :
3)
[tex]\it 4<5 \Rightarrow\sqrt4<\sqrt5 \Rightarrow2<\sqrt5 \Rightarrow2-\sqrt5<0 \Rightarrow|2-\sqrt5|=-2+\sqrt5.\\ \\ -(2+\sqrt5)=-2-\sqrt5.\\ \\ Expresia \ \ devine:\\ \\ (-2+\sqrt5-2-\sqrt5)^{1007}=(-2-2)^{1007} = (-4)^{1007} =-4^{1007}=\\ \\ =-(2^2)^{1007}=-2^{2\cdot1007}=-2^{2014}[/tex]