Răspuns :
La ex6 folosim formula a^2-2ab+b^2=(a-b)^2 iar la 7 a^2-b^2=(a-b)(a+b)

3)
a) a ( x + y ) + a ( b - x ) = a × ( x + y + b - x ) = a × ( y + b )
c) 2 c ( a + b ) + c ( 5 a - 3 b ) = c × ( 2 a + 2 b + 5 a - 3 b ) = c × ( 7 a - b )
e) a ( b + c ) + x ( b + c ) = ( b + c ) ( a + x )
g) x ( 2 x + 3 ) - 3 ( 2 x + 3 ) = ( 2 x + 3 ) ( x - 3 )
i) 2 X ( m - n ) - ( n - m ) =
= 2 X ( m - n ) - n + m =
= 2 X ( m - n ) + ( m - n ) =
= ( m - n ) ( 2 X + 1 )
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4)
a) a x + b x + a c + b c = a ( x + c ) + b ( x + c ) = ( x + c ) ( a + b )
d) 6 x + 7 y + 42 + x y =
= 6 ( x + 7 ) + y ( 7 + x ) =
= ( x + 7 ) ( 6 + y )
→ adunarea este comutativa 7 + x = x + 7
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5)
a) 2 a + b + 2 a² + a b = 2 a ( 1 + a ) + b ( 1 + a ) = ( 1 + a ) ( 2 a + b )
sau: = ( a + 1 ) ( 2 a + b )
c) 2 x² - 3 x + 4 a x - 6 a = ( x + 2 a ) ( 2 x - 3 )
= 2 x ( x + 2 a ) - 3 ( x + 2 a ) =
= ( x + 2 a ) ( 2 x - 3 )
e)
ab + ac + am + yb + yc + ym = ( a + y ) ( b + c + m )
= b ( a + y ) + c ( a + y ) + m ( a + y ) =
= ( a + y ) ( b + c + m )
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6)
a) 4 a² + 4 ab + b² = ( 2 a + b ) ² = ( 2 a + b ) ( 2 a + b )
sau:
= 4 a² + 2 ab + 2 ab + b² =
= 2 a ( a + b ) + b ( 2 a + b ) =
= (2 a + b ) ( 2 a + b )
d)
( 9 / 16) a² - 2 a b + ( 16 / 9 ) b² = ( 3 a / 4 + 4 b / 3 ) ( 3 a / 4 - 4 b / 3 )
→ aplic formula a² - b² = ( a - b ) ( a + b )
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g)
4 + 0,25² - 2 x = ( 0,5 x - 2 ) ( 0,5 x + 2 )
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7)
a) 4 x² - 1 = ( 2 x - 1 ) ( 2 x + 1 )
e) b² - n² = ( b + n ) ( b - n )
i) 49 x² - 121 a² = ( 7 x - 11 a ) ( 7 x + 11 a )