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Wwwchesaru84
a fost răspuns

A=(25^3)^9÷(4^2+3^2)^26-(2017^0+0^2017+1^2017)^4

Răspuns :

Anamariaciongaru

A= 25 la puterea 27 impartit la 24 la puterea 26- (1+0+1) la puterea a 4

A= 25-2 la puterea 4

A= 25-16=9

Sper ca te-am ajutat

Marina001

[tex]A=\frac{\left(25^3\right)^9}{\left(4^2+3^2\right)^{26}}-\left(2017^0+0^{2017}+1^{2017}\right)^4=\frac{\left(25^3\right)^9}{\left(4^2+3^2\right)^{26}}-\left(1^{2017}+0+2017^0\right)^4=\frac{\left(25^3\right)^9}{\left(4^2+3^2\right)^{26}}-\left(0+1+2017^0\right)^4=\frac{\left(25^3\right)^9}{\left(4^2+3^2\right)^{26}}-\left(1+0+1\right)^4=\frac{\left(25^3\right)^9}{\left(4^2+3^2\right)^{26}}-\left(1+0+1\right)^4=25-2^4==25-16=9[/tex]