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a fost răspuns

Cum se rezolva: [(x+5/x-5)^2 +1+ 2x+10/x-5]× x-5/4x +2

Răspuns :

{[(x+5)/(x-5)]² +1+ (2x+10)/(x-5)}· x-5/(4x +2)=
{[(x+5)/(x-5)]² +1+ (2x+10)/(x-5)}· x-5/(4x +2)=
{(x²+10x+25)/(x²-10x+25)]+(x²-10x+25)/(x²-10x+25)+[(2x+10)(x-5)/(x²-10x+25)]}·x-5/(4x+2)=
{(x²+10x+25+x²-10x+25-2x²-10x+10x-50)/(x²-10x+25)}·x-5/(4x+2)=
[0/(x²-10x+25)]·x-5/(4x+2)=
=-5/(4x+2)

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