20 va rog imi trebuie rezolvare completa pana la ora 10: 30

[tex]5<3x-15\le \:23\\5<3x-15 => 3x-15>5 =>3x>20=>x>\frac{20}{3}\\3x-15\le \:23 => 3x\le \:38 => x\le \frac{38}{3}[/tex]
combinand intervalele, rezulta
[tex]\frac{20}{3}<x\le \frac{38}{3}[/tex]