a) dupa evaporarea unei parti de apa sol. se va concentra
b)
ms1 = 50 g
c1% = 20%
c = md x 100/ms
=> md = msxc/100 = 50x10/100
=> md = 5 g
=> m.apa = ms1 - md = 50 - 5 = 45 g
=> 45x1/4 = 11,25 g s-au evaporat
=> m.apa ramasa = 45 - 11,25 = 33,75 g
=> ms2 = md + m.apa ramasa
=> ms2 = 5 + 33,75 = 38,75 g
=> c2 = 5x100/38,75
=> c2 = 12,9%