m.ip = 50 g
p = 96%
p = m.px100/m.ip
=> m.p = 96X50/100 = 48 g
48 g........n g........... m g
Mg + 2H2O => Mg(OH)2 + H2
24........2x18................58
=> m = 48x58/24 = 116 g Mg(OH)2
100% - 90% apa = 10% Mg(OH)2
=> 100% amestec .......... 10% Mg(OH)2
a g amestec.....................116 g Mg(OH)2
=> a = 116x100/10 = 1160 g amestec
=> 1160 - 116 = 1044 g apa ramasa
=> n = 48x2x18/24 = 72 g apa consumata
=> apa introdusa = apa totala + apa cons.
=> apa introd = 1044 + 72 = 1116 g apa
