Ciobanitaroxanagabri Ciobanitaroxanagabri 01-11-2018 Matematică a fost răspuns 1011^9:1011^3:1011^0=; (7^5)^12=; 5^2*5^7:5^1= 41^51:41^21*1681= (3^3)^10;3^29*(3^2)^3= (11^2)^10*(11^3)^4:(11^2)^11*11^3= (2^11)^5:92^2)^11:4= (5^8*7^7):(5^5*7^4)=
