100% - 40% impuritati = puritate = p = 60%
p% = m.px/m.ip
=> m.p = p%xp%/100 = 180 kg (Li)2CO3 pur
180 kg......... mg kg .................................... n kmoli
(Li)2CO3 + 2HCl => 2LiCl + H2O + CO2
74 .................2x36,5 ......................................1
=> md = 180x2x36,5/74 = 177,57 kg HCl
c = 36,5%
c = mdx100/ms
=> ms = mdx100/c% = 177,57x100/36,5 = 486,5 kg sol HCl
=> n = 1x180/74 = 2,43 kmoli CO2
