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Cat eate a si b daca a+b=53 si b:a=4 rest 8?

Răspuns :

a + b = 53

a : b = 4 rest 8

a = 4b + 8

4b + 8 + b = 53

5b + 8 = 53

5b = 53 - 8

5b = 45

b = 45 : 5

b = 9

a = 4 x 9 + 8 = 36 + 8 = 44

44 + 9 = 53

44 : 9 = 4 rest 8

a+b = 53 ; a:b = cat 4 rest 8 ; a= 4b+8 (teorema impartirii cu rest), inlocuim a in suma numerelor

4b+8+b = 53 ; 5b = 53-8 = 45 ; b = 45:5 = 9 ; a = 53-9 = 44 ;