Corectie: 1 + 3 + 5 + 7 ( in loc de 6 )
B = 1 + 3 + 5 + 7 + ..... + 2017
→ stabilesc cati termeni are suma cu ratia = 2
( 2017 - 1 ) : 2 + 1 = 2016 : 2 + 1 = 1009 termeni are suma
→ aplic formula sumei lui Gauss
B = 1009 × ( 1 + 2017 ) : 2
B = 1009 × 2018 : 2
B = 1009 × 1009