raportul de maas mC:mH= 83,7: 16,3
RAPORTUL MOLAR: nC : nH= 83,7/12 : 16,3/1,
deoarece A,C=12g/mol A,H=1g/mol
= 6,97 : 16,3 impartind prin cel mai mic
= 1: 2,33
F.M: (C1 H2,33)n are masa molara:
n(12+2,33)= 86---> n=6----------------> C6H14 ----> HEXAN
CH3-CH2-CH2-CH2-CH2-CH3