2-metil-1,4-hexadienei ...... H2C=C(CH3)-CH2-CH=CH-CH3
H2C=C(CH3)-CH2-CH=CH-CH3 + 8[O] _KMnO4/H+_>
CO2 + H2O + O=C(CH3)-CH2-COOH + HOOC-CH3
O=C(CH3)-CH2-COOH = acid 3-cetobutanoic (acid 3-cetobutiric)
CH3-COOH = acid acetic
explicatie:
H2C=/=C(CH3)-CH2-CH=/=CH-CH3 ti-am aratat unde are loc scindarea (atacul [O] ) si ce va genera
fragmentul H2C=/ genereaza CO2 + H2O
fragmentul /=C(CH3)-CH2-CH=/ genereaza O=C(CH3)-CH2-COO
fragmentul =CH-CH3 genereaza CH3-COOH
Sper ca info iti sunt pe inteles si de ajutor...!
