Răspuns :
ax3-7:11-2=5
3a-7:11=5+2
=7
3a-7=7x11
3a-7=77
3a=77+7
3a=84
a=28
V: 28x3-7:11-2=5
Notam cu x=numarul necunoscut
Aplicam metoda problemei inverse:
5=[(3x-7)÷11]-2
7=(3x-7)÷11
77=3x-7
84=3x
x=28
ax3-7:11-2=5
3a-7:11=5+2
=7
3a-7=7x11
3a-7=77
3a=77+7
3a=84
a=28
V: 28x3-7:11-2=5
Notam cu x=numarul necunoscut
Aplicam metoda problemei inverse:
5=[(3x-7)÷11]-2
7=(3x-7)÷11
77=3x-7
84=3x
x=28