Răspuns :
=(2^3)^33÷[(2^2)^32×2^34+(2^25)^5÷(2^4×2^23)+(1-1)^32×4]
=2^(3×33)÷[2^(2×32)×2^34+2^(25×5)÷ 2^(4+23)+0^32×4]
=2^99÷[2^64×2^34+2^125÷2^27+0)
=2^99÷(2^98+2^98)
=2^99÷(2×2^98)
=2^99÷2^99
=1
X^y+y^x=1^y+y^1=1+y
=(2^3)^33÷[(2^2)^32×2^34+(2^25)^5÷(2^4×2^23)+(1-1)^32×4]
=2^(3×33)÷[2^(2×32)×2^34+2^(25×5)÷ 2^(4+23)+0^32×4]
=2^99÷[2^64×2^34+2^125÷2^27+0)
=2^99÷(2^98+2^98)
=2^99÷(2×2^98)
=2^99÷2^99
=1
X^y+y^x=1^y+y^1=1+y