👤
a fost răspuns

Calculati b) [3/2×3/3+2/54:2/52+(3/5)/4:3/20]:31

Răspuns :

Mikelina

[3/2×3/3+2/54:2/52+(3/5)/4:3/20]:31=

(3/2+2/54×52/2+3/5×1/4:3/20):31=

(3/2+52/54+3/20:3/20):31=

(3/2+26/27+3/20×20/3):31=

(3/2+26/27+1):31=

(133/54+1):31=

187/54:31=

187/54×1/31=

187/1674=

0,111

Alte intrebari