Răspuns :
α) = (2²⁰¹⁷ − 2²⁰¹⁶−2²⁰¹⁵) ÷2⁵ ÷(2⁴)⁵⁰²+1×1=
= 2²⁰¹⁵×(2² − 2−1) ÷2⁵÷2²⁰⁰⁸ +1 =
= 2²⁰¹⁵× 1 ÷2⁵÷2²⁰⁰⁸+1=
= 2²⁰¹⁵−⁵−²⁰⁰⁸ + 1=
= 2² +1= 4+1=5
b)= [2017⁰ +(3³)²⁷÷(3²)⁴⁰]⁵⁰ ÷(2⁵)²⁰=
= [1 + 3⁸¹ ÷ 3⁸⁰ ]⁵⁰ ÷ 2¹⁰⁰ =
= [ 1+3]⁵⁰ ÷ 2¹⁰⁰=
= 4⁵⁰ ÷ 2¹⁰⁰=
= (2²)⁵⁰ ÷ 2¹⁰⁰= 2¹⁰⁰ ÷ 2¹⁰⁰ = 2⁰ = 1
C)= 2⁸ ÷ (2²)³+ 3⁴÷( 64−36−1)=
=. 2⁸ ÷ 2⁶ + 3⁴÷ 27 =
= 2⁸−⁶ + 3⁴ ÷ 3³ =
= 2² + 3 = 4+3= 7