Răspuns :
3t²-t+4-8=0
3t²-t-4=0
delta=1+48=49
x1= 1-7/6=-1
x2=1+7/6=4/3
sper ca te-am ajutat!
3t²-t-4=0
delta=1+48=49
x1= 1-7/6=-1
x2=1+7/6=4/3
sper ca te-am ajutat!
3t²-t+4=0
a=3
b=-1
c=4
Δ=b²-4ac
Δ=(-1)²-4·3·4=1-48=-47
t₁₂=(-b₊₋√Δ)/2a
t₁=(1-√-47)/6=(1-47i)/6
t₂=(1+47i)/6
a=3
b=-1
c=4
Δ=b²-4ac
Δ=(-1)²-4·3·4=1-48=-47
t₁₂=(-b₊₋√Δ)/2a
t₁=(1-√-47)/6=(1-47i)/6
t₂=(1+47i)/6