0,(3) = 3/9 = 1/3
2,(45) = (245 - 2)/99 = 243/99
0,1(26) = (126 - 1)/99 = 125/990
2 intregi 5/11 = (2×11+5)/11 = 27/11
= ( - 1/3 + 243/99 + 125/990) : ( - 1/3 + 27/11 + 25/198) - 1998
= ( - 330/990 + 2430/990 + 125/990) : (-66/198 + 27×18/198 + 25/198) - 1998 =
= 2225/990 : ( - 66/198 + 486/198 + 25/198) - 1998 =
= 2225/990 : 445/198 - 1998 =
2225/990 × 198/445 - 1998 =
2225/5 × 1/445 - 1998 =
445/445 - 1998 =
1 - 1998 =
- 1997
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