M,Na= 23g/mol
M,NaOH= 40g/mol
calculez din ecuatia chimica masa de NaOH rezultata
2mol...........2mol............2mol sau, in grame
2Na + 2H2O-----> 2NaOH + H2
2x23g........2x18g,,,,,,,,,,,,2x40g
4,6g................x ............................y
x= 3,6g apa---> apa ramasa nereactionata m,apa= 100.-3,6
y= 8gNaOH......aceasta este masa dizolvata in solutie, md
c= mdx100/ms, unde ms= md+m,apa
md= 8g
ms= 8+(100-3,6)=104,4g
c= 8x100/ 104,4=.............................calculeaza !!!!