Răspuns :
d=î*c+r
d:2009=c , rest c*10
2019:2009=1 , rest 10 , indeplineste conditiile
n=2009a +r
r=10a
n=2009a +10a = 2019a
r < 2009
r divizibil cu 10 ⇒
r max= 2000 ⇒a=200 ⇒ n =2009·200+ 2000 = 403200.
d=î*c+r
d:2009=c , rest c*10
2019:2009=1 , rest 10 , indeplineste conditiile
n=2009a +r
r=10a
n=2009a +10a = 2019a
r < 2009
r divizibil cu 10 ⇒
r max= 2000 ⇒a=200 ⇒ n =2009·200+ 2000 = 403200.