Răspuns :
(b+72+b):(b+72-b)=5 rest 2
(2b+72):72=5 r 2
2b+72=5×72+2
2b+72=362
2b=362-72
2b=290
b=290÷2
b=145
a=145+72
a=217
(2b+72):72=5 r 2
2b+72=5×72+2
2b+72=362
2b=362-72
2b=290
b=290÷2
b=145
a=145+72
a=217
Cerinta: Sa se determine cele doua numere ( a si b ).
a = b + 72
( a + b ) : ( a - b ) = 5 rest 2
a - b = 72 → diferenta numerelor ⇔ am dedus-o din relatia a = b + 72
( a + b ) : 72 = 5 rest 2
a + b = 5 × 72 + 2 → teorema impartirii cu rest
a + b = 360 + 2
a + b = 362 → suma numerelor
( b + 72 ) + b = 362
2 × b = 362 - 72
2 × b = 290
b = 290 : 2
b = 145
a = 145 + 72 ⇒ a = 217