H2SO4 + Mg(OH )2 =MgSO4 +2H2O
Comp. procentuala a Mg(OH)2 prin masa moleculara
M=24+2.16 + 2=58 ------>1mol=58 g Mg( OH)2
58 g Mg ( OH )2----------24g Mg----------32g O---------2g H
100g----------------------------xg-------------------yg-------------zg
x=100 .24 :58=41,37 la suta Mg
y=100 .32 : 58=55,17 la suta O
z=100.2 :58=3,44 la suta H