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Grupeaza convenabil termeni adunarilor pentru a afla suma 235+2109+991+1465= al doilea 310+1290+3828+490+1182+1250= si al treilea1583+275+3417+2275=

Răspuns :

a) 2109+991+235+1465
3100+1700=4800

b) 3828+1182+1250+310+310+490=7370

c) 1583+3417+275+2275=8550

A) 2109+991+1465+235=
3100+1700=4800

B) 3828+1182+1250+490+310+129=
5010+1740+439=
7089

C) 1583+3417+2275+275=
5000+3550=8550