[tex](\frac{5}{2}-\frac{2}{5})+\frac{11}{30}+\frac{12}{3}+(-1)*2005=\\ \\ =\frac{25-4}{10}+\frac{11}{30}+\frac{12}{3}-2005=\\ \\ =\frac{21}{10}+\frac{11}{30}+\frac{12}{3}-\frac{2005}{1}=\\ \\ =\frac{63+11+120-60150}{30}=-\frac{59956}{30}=-\frac{29978}{15}.[/tex]
/rfd
