|x+2|=2
x+2=2...x=0 si
x+2=-2...x=-4
a doua nu e clara, nu ai inchis modulul
daca e 10-|2x-√3|=7 . atunci
|2x-√3|=3
deci 2x-√3=3 ...... x=(3+√3)/2
si 2x-√3=-3...x=(-3+√3)/2
|-x-3|=1=|x+3| pt .ca |ceva|=|-ceva|
x+3=1...x=-2 si x+3=-1...x=-4
|x+4|=-2, x∈∅pt. ca |orice|≥0 si -2<0
