C2H2 + 5/2O2 => 2CO2 + H2O Hr1
C6H6 + 15/2O2 => 6CO2 + 3H2O Hr2
____________________
3C2H2 ===> C6H6 Hr3
egalam reactiile 1 si 2 cu coef. fiecarui termen din reactia globala (Hr3)
Hr1 x 3
Hr2 x (-1)
=> Hr3 = Hr2 + Hr2 (din teorie)
=> cazul nostru avem
Hr3 = 3xHr1 + (-1)Hr2
=> Hr3 = 3x1297,56 - 3345,28
=> Hr3 = 547, 4 kj
