[tex]3 - \sqrt{ {x}^{2} + 3 } = x \\ \\ 3 - \sqrt{ {x}^{2} + 3 } - 3 = x - 3 \\ \\ - \sqrt{ {x}^{2} + 3 } = x - 3 \\ \\ - 1 \times ( - \sqrt{ {x}^{2} + 3 }) = - 1x - 1 \times ( - 3) \\ \\ \sqrt{ {x}^{2} + 3 } = - x + 3 \\ \\ { \sqrt{ {x}^{2} + 3 } }^{2} = {( - x + 3)}^{2} \\ \\ {x}^{2} + 3 = {(3 - x)}^{2} \\ \\ {x}^{2} + 3 = 9 - 6x + {x}^{2} \\ \\ 3 = 9 - 6x \\ \\ 6x + 3 = - 6x + 6x + 9 \\ \\ 6x + 3 = 9 \\ \\ 6x + 3 - 3 = 9 - 3 \\ \\ 6x = 9 - 3 = 6 \\ \\ 6x : 6 = 6 : 6 \\ \\ x = 6 : 6 = 1 \\ \\ 3 - \sqrt{ {1}^{2} + 3 } = 1 \\ \\ 1 = 1 \\ \\ = > x = 1 [/tex]
