Răspuns :
raport atomic=1:1:4
masa moleculara CuSo4=ACu+AS+4AO=64+32+4x16=asta faci tu
raport de masa=64:32:16=4:2:1
compozita procentuala =7g..4gCu.....2gS....1gO
100g.....xgCu.....ygS....zgO
x=4x100:7
y=2x100:7
z=1x100:7
masa moleculara CuSo4=ACu+AS+4AO=64+32+4x16=asta faci tu
raport de masa=64:32:16=4:2:1
compozita procentuala =7g..4gCu.....2gS....1gO
100g.....xgCu.....ygS....zgO
x=4x100:7
y=2x100:7
z=1x100:7
raport atomic Cu:S:O=1:1:4
masa moleculara CuSO4=A Cu + A S + 4*A oxigen = 64+32+4*16=160g/mol
raport de masa Cu:S:O=A Cu: A S: 4*A oxigen =64:32:4*16=64:32:64=>2:1:2
compozitia procentuala
%Cu=mCu/masa molara sulfat * 100=64/160 *100 =40%
%S=m S/masa molara sulfat * 100=32/160 * 100=20%
%O=m O/masa molara sulfat * 100=4*16/160 * 100=40%
masa moleculara CuSO4=A Cu + A S + 4*A oxigen = 64+32+4*16=160g/mol
raport de masa Cu:S:O=A Cu: A S: 4*A oxigen =64:32:4*16=64:32:64=>2:1:2
compozitia procentuala
%Cu=mCu/masa molara sulfat * 100=64/160 *100 =40%
%S=m S/masa molara sulfat * 100=32/160 * 100=20%
%O=m O/masa molara sulfat * 100=4*16/160 * 100=40%