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a fost răspuns

CALCULATI IN MODUL CEL MAI EFICIENT:
A]  [tex] \frac{3}{4} [/tex]*1[tex] \frac{3}{5} [/tex]+1[tex] \frac{3}{5} [/tex]*1[tex] \frac{3}{8} [/tex]-1[tex] \frac{1}{2} [/tex]*1[tex] \frac{3}{5} [/tex]=

B]4[tex] \frac{1}{9} [/tex]*[tex] \frac{5}{8} [/tex]+3[tex] \frac{5}{9} [/tex]*[tex] \frac{5}{8} [/tex]+1[tex] \frac{1}{3} [/tex]*[tex] \frac{5}{8} [/tex]=

Răspuns :

A] 3/4x8/5+8/5x11/8-3/2x8/5=
8/5(3/4+11/8-3/2)=
8/5x(6+11-12)/8=
8/5x7/8=7/5

b)37/9x5/8+32/9x5/8+4/3x5/8=
5/8x(37/9+32/9+4/3)=
8/5x(69/9+4/3)=
8/5x(69+12)/9=
8/5x81/9=
8/5x9=72/5

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