Urgent ! Problema 3 si problema 4 ! Va rog.
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ΔHr = ΔH,f,H2O -ΔH,f,H2O2---> ΔH,f,H2O2= ΔH.f,H2O-ΔHr
=-285kj- (-98,8)kj== - 189,2 kj reactie exoterma !
5. rx: Br2(L)--------> Br2(G)
aceasta transformare se obtine din diferenta dintre a doua reactie si prima:
rx=r2-r1 ---> ΔH= ΔHr2-ΔHr1= -72kj-(-102,9)kj=30.9kj
160gBr2(1mol).........40,9kg
3,2g.....................X...................................calculeaza !!!!!