C6H5-CH3 + nCl2 ---lumina--> C6H5-CH3-nCln + nHCl
M.moleculara = 92 + 34,5n g/mol
Daca la 100% .............. avem.............52,174% Cl
la 92+34,5n ..... vom avea.... 34,5n
=> n = 3
=> C6H5-CH3-3Cl3 => Fm : C6H5-CCl3 triclorofenilmetanul (clorura de benzilidin)
