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daca a+b33 si a+c=11 calculati 5*a+3*b+2*c

Răspuns :

Mikelina

a+b=33

a+c=11

5a+3b+2c=

(5a=3a+2a)

=3a+2a+3b+2c=

3(a+b)+2(a+c)=

3×33+2×11=

99+22=

121


Mădălinuşca

a+b=33 => a=33-b

a+c=11 =>c=11-a=11-(33-b)=11-33+b=b-22

5*a+3*b+2*c=5*(33-b)+3*b+2*(b-22)=165-5b+3b+2b-44=121

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