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1+{2×[3+(x-4)×5]:6}×7=8

Răspuns :

Profudefizica

1+[2*(3+5x-20):6]*7=8

1+[(6+10x-40):6]*7=8

[(6+10x-40):6]*7=8-1=7

(6+10x-40):6=1

deci 6+10x-40=6, 10x-40=0   10x=40, deci x=4



Ahmed1985
{2×[3+(x-4)×5]:6}×7=8−1=7

2×[3+(x-4)×5]:6= 7:7=1

2×[3+(x-4)×5]=1×6=6

3+(x-4)×5= 6:2= 3

(X-4)×5= 3−3 =0

X-4 = 0:5 = 0

X= 0+4= X

X= 4

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