Răspuns :
suma lui Gauss:
s= n(n+1)/2
s= 200(200+1)/2
s= 200•201/2
s= 40200/2
s= 20100
=> n fiind ultimul termen
s= n(n+1)/2
s= 200(200+1)/2
s= 200•201/2
s= 40200/2
s= 20100
=> n fiind ultimul termen
S = 1 + 2 + 3 + ...... + 200
S = 200 × ( 1 + 200 ) / 2 → aplic formula sumei lui Gauss
S = 100 × 201
S = 20 100