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5/6 + 7/3 -2 intregi 3/4

Răspuns :

Danamaria06

[tex] \frac{5}{6} + \frac{7}{3} - 2 \frac{3}{4} = [/tex]
[tex] \frac{5}{6} + \frac{7}{3} - \frac{11}{4 } = [/tex]
[tex] \frac{5}{6} amplificat \: cu \: 2 = \frac{10}{12} [/tex]
[tex] \frac{7}{3} amplificat \: cu \: 4 = \frac{28}{12} [/tex]
[tex] \frac{11}{4} \: amplificat \: cu \: 3 = \frac{33}{12} [/tex]
[tex] \frac{10}{12} + \frac{28}{12} - \frac{33}{12} = \frac{5}{12} [/tex]

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